Real World - Shirts
A store ordered 536 shirts from a factory. The factory sent 100 each day for three days. Then, they sent 86 the next two days. How many more shirts do they still need to send?
Explain how your students solved this problem.
posted by Mrs. Kimball @ 4:41 PM
5 Comments:
My students solved this type of problem by translating the written expressions into algebraic equation. They first defined a variable (the number of shirts still needed). They wrote the algebraic equation, combined like terms and solved for the variable by performing inverse operations. They came up with a final answer of 64 shirts which they checked by "plugging in" the original equation.
This was very easy for my kids. They made this numerical expression: 536 - 100(3) - 86(2)and got the answer of 64.
The students in my class subtracted 300 from 536 and then they subtracted 86 two times. To find the final answer they subtract the number they got from the 536 to find the number of shirts still needed.
The students added up all of the shirts recieved over the 5 days. 100+100+100+86+86=472. Then they subracted 472 from the original amount ordered, 536. 536-472=64 shirts
Most of my students solved this problem in steps. They multiplied 100 by 3, and then they multiplied 86 by 2. They added the answers to both of these problems and then subtracted the total from 536.
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